Surprisingly there are only three numbers that can be written as the sum of fourth powers of their digits:
1634 = 14 + 64 + 34 + 44
8208 = 84 + 24 + 04 + 84
9474 = 94 + 44 + 74 + 44
As 1 = 14 is not a sum it is not included.
The sum of these numbers is 1634 + 8208 + 9474 = 19316.
Find the sum of all the numbers that can be written as the sum of fifth powers of their digits.
C CODE:
#include<stdio.h>#include<limits.h>
main()
{
int counter=0;
int i;
int sum=0;
int result=0;
for(i=10;i<=355000;i++)
{
int t=i;
sum=0;
while(t!=0)
{
sum=sum+pow(t%10,5);
t=t/10;
}
if(sum==i){result=result+i;}
}
printf("%d",result);
}
TIME TAKEN:
220ms
RESULT:
443839
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