You are given the following information, but you may prefer to do some research for yourself.
C PROGRAM:
main()
{
int counter=0;
int n;
int k=1;
int i;
int year;
for(year=1900;year<=2001;year++)
{
for(i=0;i<=11;i++)
{
if(i==0||i==2||i==4||i==6||i==7||i==9||i==11)
k=k+(31%7);
if(i==3||i==5||i==8||i==10)
k=k+(30%7);
if(i==1)
{
if(year%100==0&&year%400==0)
{
k=k+(29%7);
}
if(year%100!=0&&year%4==0)
{
k=k+(29%7);
}
if(year%4!=0)
k=k+(28%7);
}
if(k%7==0)counter++;
}
if(year==1900){counter=-counter;}
}
printf("%d",counter);
}
- 1 Jan 1900 was a Monday.
- Thirty days has September,
April, June and November.
All the rest have thirty-one,
Saving February alone,
Which has twenty-eight, rain or shine.
And on leap years, twenty-nine. - A leap year occurs on any year evenly divisible by 4, but not on a century unless it is divisible by 400.
C PROGRAM:
main()
{
int counter=0;
int n;
int k=1;
int i;
int year;
for(year=1900;year<=2001;year++)
{
for(i=0;i<=11;i++)
{
if(i==0||i==2||i==4||i==6||i==7||i==9||i==11)
k=k+(31%7);
if(i==3||i==5||i==8||i==10)
k=k+(30%7);
if(i==1)
{
if(year%100==0&&year%400==0)
{
k=k+(29%7);
}
if(year%100!=0&&year%4==0)
{
k=k+(29%7);
}
if(year%4!=0)
k=k+(28%7);
}
if(k%7==0)counter++;
}
if(year==1900){counter=-counter;}
}
printf("%d",counter);
}
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